Physics

Angular Acceleration and Centripetal Acceleration

Angular acceleration refers to the rate of change of angular velocity of an object as it moves in a circular path. It is measured in radians per second squared. Centripetal acceleration, on the other hand, is the acceleration directed towards the center of the circular path and is responsible for keeping an object moving in a curved path.

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8 Key excerpts on "Angular Acceleration and Centripetal Acceleration"

Index pages curate the most relevant extracts from our library of academic textbooks. They’ve been created using an in-house natural language model (NLM), each adding context and meaning to key research topics.
  • Biomechanics of Human Motion
    eBook - ePub

    Biomechanics of Human Motion

    Applications in the Martial Arts, Second Edition

    • Emeric Arus, Ph.D.(Authors)
    • 2017(Publication Date)
    • CRC Press
      (Publisher)

    ...More precisely, the angular speed tells us the change in angle per unit of time, which is measured in radians/s. Angular speed can also be measured in degrees, for example, 360 o /s. Even if the term angular speed is equivalent to rotational velocity, there is a difference, which is the rotation (revolution) per minute, for example, 60 rpm. Angular speed represents the magnitude of angular velocity. The angular velocity, whose sign is also a Greek letter omega (ω), is a vector quantity; that is why in most physics books or other books, the authors use the terms angular velocity and angular speed interchangeably. The magnitude of angular velocity can be described in two terms. One is the average angular velocity, which represents the angular displacement of an object between two points of an angle such as θ 1 and θ 2 at the time intervals t 1 and t 2, respectively. Then, the equation for average angular velocity is = (θ 2 -θ 1 / t 2 - t 1)= (∆θ/∆ t); the other term for the magnitude is the instantaneous angular velocity, which is the limit of the magnitude ratio as Δ t approaches 0. The formula is: ω = lim as Δ t → 0 Δθ/Δ t = dθ/d t, both and ω being measured in m/s. To find out the average angular acceleration and the instantaneous angular acceleration, we proceed in an analogous fashion to linear velocities and accelerations. The average angular acceleration () of a rotating body in the interval from t 1 to t 2 can be defined using the following formula, where ω represents the instantaneous angular velocities. The formula for average angular acceleration =ω 2 -ω 1 / t 2 - t 1 = ∆ω/∆ t,and the instantaneous angular acceleration α = lim as Δ t → 0 Δω/Δ t = dω/d t, both and α being measured in rad/s 2. Speaking about angular motion, we should mention two different and important accelerations. One of these is the so-called radial component of the linear acceleration that is named radial acceleration, also called centripetal acceleration...

  • BIOS Instant Notes in Sport and Exercise Biomechanics
    • Paul Grimshaw, Neil Fowler, Adrian Lees, Adrian Burden(Authors)
    • 2007(Publication Date)
    • Routledge
      (Publisher)

    ...Angular acceleration is defined as the rate of change of angular velocity and is calculated by angular velocity (final – initial) divided by the time taken. Clockwise and anti-clockwise rotation Clockwise rotation is movement in the same direction as the hands of a clock (i.e., clockwise) when you look at it from the front. Clockwise rotation is given a negative symbol (−ve) for representation. Anti-clockwise rotation is the opposite movement to clockwise rotation and it is given a positive symbol (+ve) for representation. Absolute and relative angles An absolute angle is the angle measured from the right horizontal (a fixed line) to the distal aspect of the segment or body of interest. A relative joint angle is the included angle between two lines that often represent segments of the body (i.e., the relative knee joint angle between the upper leg (thigh) and the lower leg (shank)). In a relative angle both elements (lines) that make up the angle can be moving. Included angle and vertex An included angle is the angle that is contained between two lines that meet or cross (intersect) at a point. Often these lines are used to represent segments of the human body. The vertex is the intersection point of two lines. In human movement the vertex is used to represent the joint of interest in the human body (i.e., the knee joint) Angular motion Angular motion is rotatory movement about an imaginary or real axis of rotation and where all parts on a body (and the term body need not necessarily be a human body) or segment move through the same angle. Angular kinematics describes quantities of angular motion using such terms as angular displacement, angular velocity and angular acceleration. Fig. A3.1 identifies two examples of angular motion in more detail. Angular distance or displacement (scalar or vector quantity) is usually expressed in the units of degrees (where a complete circle is 360 degrees)...

  • Mechanical Design for the Stage
    • Alan Hendrickson(Author)
    • 2012(Publication Date)
    • Routledge
      (Publisher)

    ...Constant velocity implies a constant speed and a constant direction—in other words perfectly straight line motion. Whenever rotation occurs, all points on a spinning object, except those directly on the axis of rotation, constantly change direction. Change, be it in the speed of an object or in the direction of its travel, requires an acceleration. Centripetal acceleration is the name given to the always-directed-inward acceleration that must occur during rotation to keep an object spinning in a circle (see Figure 7.4c). Mathematically, centripetal acceleration equals Figure 7.4 Illustration of the terms involved in: a. Angular and linear displacement, b. Angular and linear speed and acceleration, c. Tangential and centripetal acceleration. (In both b. and c. rotational speed and acceleration are indicated in an easily understood way. The actual vectors for rotational velocity and acceleration would be shown by arrows along the axis of rotation, straight out of the page.) a c e n t r i p e t a l = v 2 r = r ω 2 Newton’s second law states that force is required to accelerate mass, and so a centripetal force can be defined. F c e n t r i p e t a l = m a c e n t r i p e t a l = m r ω 2 If you were to tie a weight to a string and spin it around above your head, the tension in the line would equal F centripetal. The cohesive forces within the steel of a shaft supply F centripetal, keeping the shaft from flying apart as it spins (though there are limits to the speed it can withstand)...

  • Instant Notes in Sport and Exercise Biomechanics
    • Paul Grimshaw, Michael Cole, Adrian Burden, Neil Fowler(Authors)
    • 2019(Publication Date)
    • Garland Science
      (Publisher)

    ...Angular distance is expressed with magnitude only. Degrees and radians Units that are used to measure angular displacement (where a circle = 360 degrees or 2π radians). 1 radian is approximately 57.3 degrees. Angular velocity and angular acceleration Angular velocity is the angular displacement divided by the time taken. Angular acceleration is the rate of change of angular velocity and is calculated by change in angular velocity (final – initial) divided by the time taken. Clockwise and anti-clockwise rotation Clockwise rotation is movement in the same direction as the hands of a clock when you look at it from the front. Clockwise rotation is given a negative symbol (−ve) for representation. Anti-clockwise rotation is the opposite movement to clockwise rotation and it is given a positive symbol (+ ve) for representation. FURTHER READING The following resources provide additional reading around the assessment of angular motion in sport and human movement. 1    Gholipour, M., Tabrizi, A., & Farahmand, F. (2008). Kinematics analysis of lunge fencing using stereophotogrammetry. World Journal of Sport Sciences, 1 (1), 32–37. 2    Hiroyuki, N., Wataru, D., Shinji, S., Yasuo, I., & Kyonosuke, Y. (2002). A kinematic study of the upper-limb motion of wheelchair basketball shooting in tetraplegic adults. Journal of Rehabilitation Research and Development, 39 (1), 63–71. C2 LINEAR-ANGULAR MOTION Paul Grimshaw The linear and angular components of movement are linked by a mathematical relationship. Specific formulae exist that show how the linear translation of points on a rotating object (or segment) can be determined. Often within biomechanics it is necessary to understand and apply this relationship. For example, in the case of the soccer kick, it is the angular movement of the leg that creates the resultant linear velocity (derived from the horizontal and vertical components) that is applied to the ball in order to give it trajectory and motion...

  • Higher Engineering Science
    • William Bolton(Author)
    • 2012(Publication Date)
    • Routledge
      (Publisher)

    ...It can be expressed as: [20] 3 Angular acceleration The average angular acceleration over some time interval is the change in angular velocity during that time divided by the time: [21] The unit is rad/s 2. The instantaneous angular acceleration a is the change in angular velocity with time when the time interval tends to zero. It can be expressed as: [22] 4.4.1 Motion with constant angular acceleration For a body rotating with a constant angular acceleration α, when the angular velocity changes uniformly from ω 0 to co in time t, as in Figure 4.19, equation [ 21 ] gives: Figure 4.19 Uniformly accelerated motion and hence: ω = ω 0 + at [23] The average angular velocity during this time is ½(ω + ω 0) and thus if the angular displacement during the time is θ: Substituting for co using equation [ 23 ]: Hence: θ = ω 0 t + ½at 2 [24] Squaring equation [ 23 ] gives: Hence, using equation [ 24 ]: [25] Example An object which was rotating with an angular velocity of 4 rad/s is uniformly accelerated at 2 rad/s. What will be the angular velocity after 3 s? Using equation [ 23 ]: ω = ω 0 + at = 4 + 2 × 3 = 10 rad/s Example The blades of a fan are uniformly accelerated and increase in frequency of rotation from 500 to 700 rev/s in 3.0 s. What is the angular acceleration? Since ω = 2π f, equation [ 23 ] gives: 2π × 700 = 2π × 500 + a × 3.0 Hence a = 419 rad/s 2. Example A flywheel, starting from rest, is uniformly accelerated from rest and rotates through 5 revolutions in 8 s. What is the angular acceleration? The angular displacement in 8 s is 2π × 5 rad. Hence, using equation [ 24 ], i.e. θ = ω 0 t + ½ at 2 : 2π × 5 = 0 + ½ a × 8 2 Hence the angular acceleration is 0.98 rad/s 2. Revision 13 A flywheel rotating at 3.5 rev/s is accelerated uniformly for 4 s until it is rotating at 9 rev/s...

  • Science and Mathematics for Engineering
    • John Bird(Author)
    • 2019(Publication Date)
    • Routledge
      (Publisher)

    ...Rewriting equation (7) with v 2 as the subject of the formula gives: v 2 = v 1 + at (8) where v 2 = final velocity and v 1 = initial velocity. Angular acceleration α is defined as the rate of change of angular velocity with respect to time. For an object whose angular velocity is increasing uniformly: angular acceleration = c h a n g e o f a n g u l a r v e l o c i t y t i m e t a k e n i.e. α = ω 2 - ω 1 t (9) The unit of angular acceleration is radians per second squared (rad/s 2). Rewriting equation (9) with ω 2 as the subject of the formula gives: ω 2 = ω 1 + α t (10) where ω 2 = final angular velocity and ω 1 = initial angular velocity. From equation (6), v = ωτ. For motion in a circle having a constant radius r, v 2 = ω 2 τ and v 1 = ω 1 τ, hence equation (7) can be rewritten as: a = ω 2 r - ω 1 r t = r (ω 2 - ω 1) t But from equation (9), ω 2 - ω 1 t = α Hence a = r α (11) Problem 3. The speed of a shaft increases uniformly from 300 revolutions per minute to 800 revolutions per minute in 10 s. Find the angular acceleration, correct to 3 significant figures From equation (9), α = ω 2 - ω 1 t Initial angular velocity ω 1 = 3 0 0 r e v / m i n = 3 0 0 ∕ 6 0 r e v / s = 3 0 0 × 2 π 6 0 r a d / s, final angular. velocity ω 2 = 8 0 0 × 2 π 6 0 r a d / s a n d t i m e t = 10 s. Hence, angular acceleration α = 8 0 0 × 2 π 6 0 - 3 0 0 × 2 π 6 0 1 0 r a d / s 2 = 5 0 0 × 2 π 6 0 × 1 0 = 5.24 rad/s 2 Problem 4. If the diameter of the shaft in Problem 3 is 50 mm, determine the linear acceleration of the shaft on its...

  • Engineering Science
    • W. Bolton(Author)
    • 2015(Publication Date)
    • Routledge
      (Publisher)

    ...What is the angular acceleration? The angular displacement in 8 s is 2π x 5 rad. Hence, using the equation θ = ω 0 t + ½α t 2 : 2 π x 5 = 0 + ½ α x 8 2 Hence the angular acceleration is 0.98 rad/s 2. Example A wheel starts from rest and accelerates uniformly with an angular acceleration of 4 rad/s 2. What will be its angular velocity after 4 s and the total angle rotated in that time? ω = ω 0 + αt = 0 + 4 x 4 = 16 rad/s θ = ω 0 t + ½α t 2 = 0 + 1/2 x 4 x 4 2 = 32 rad. 5.3 Relationship between linear and angular motion Figure 5.2 Angular motion Consider the radial arm of radius r in Figure 5.2 rotating from OA to OB. When the radial arm rotates through angle θ from OA to OB, the distance moved by the end of the radial arm round the circumference is AB. One complete revolution is a rotation through 2 π rad and point A moves completely round the circumference, i.e. a distance of 2 π r. Thus a rotation through an angle of 1 rad has A moving a circumferential distance of r and so a rotation through an angle θ has point A moving through a circumferential distance of rθ. Hence, if we denote this circumferential distance by s then: s = rω If the point is moving with constant angular velocity ω then in time t the angle rotated will be ωt and so s = rωt. But s/t is the linear speed v of point A round the circumference. Hence: v = rω Now consider the radial arm rotating with a constant angular acceleration. If the point A had an initial linear velocity u then its angular velocity ω 0 would be given by u = rω 0. If it accelerates with a uniform angular acceleration α to an angular velocity ω in a time t then α = (ω - ω 0)/ t. If the point A now has a linear velocity v then v = rω...

  • The Practice of Engineering Dynamics
    • Ronald J. Anderson(Author)
    • 2020(Publication Date)
    • Wiley
      (Publisher)

    ...The magnitude of the radial velocity is often referred to in reference books as and the Coriolis acceleration is seen written as where the reader is left to determine its direction from a complicated set of rules. Consideration of Equations 1.45, 1.46, 1.47 shows that there are two very different types of terms that combine to form the Coriolis acceleration with its remarkable 2. The two terms are equal in magnitude and direction (i.e. each is). One of these arises from part of the rate of change of magnitude of the tangential velocity of. The second arises from the rate of change of direction of the radial velocity of. is the centripetal acceleration. In 2D circular motion. this is commonly written as and points toward the center of the circle. For the general points and used here, the centripetal acceleration points from to. It is possible to visualize the acceleration components using a simple graphical construction. As an example, we can use the slider in a slot system shown in Figure 1.4 for which we have already derived both the velocity (Equation 1.19) and the acceleration (Equation 1.20) in body fixed coordinates. Remember that rates of change of magnitude are aligned with the vector that is changing and rates of change of direction are perpendicular to the original vector and are pointed in the direction that the tip of the vector would move if it had the prescribed angular velocity and were simply rotating about its tail. Figure 1.7 The velocity and acceleration components of the slider. Figure 1.7 shows the two components of the velocity of the slider in the inner circle. A component is labeled with a to indicate that it results from a rate of change of magnitude or a to show that it results from a rate of change of direction...