Deductive Geometry
eBook - ePub

Deductive Geometry

  1. 192 pages
  2. English
  3. ePUB (mobile friendly)
  4. Available on iOS & Android
eBook - ePub

Deductive Geometry

About this book

This concise review examines the geometry of the straight line, circle, plane, and sphere as well as their associated configurations, including the triangle and the cylinder. Aimed at university undergraduates, the treatment is also useful for advanced students at the secondary level.
The straightforward approach begins with a recapitulation of previous work on the subject, proceeding to explorations of advanced plane geometry, solid geometry with some reference to the geometry of the sphere, and a chapter on the nature of space, including considerations of such properties as congruence, similarity, and symmetry. The text concludes with a brief account of the elementary transformations of projection and inversion. Numerous examples appear throughout the book.

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Information

Year
2016
Print ISBN
9780486802831
eBook ISBN
9780486809250
THREE
Some Circle Theorems
1. The Theorem of Ptolemy
Fig. 23
(i) A quadrilateral inequality
THE PROBLEM. ABC is a given triangle and D an arbitrary point. (The diagram shows a typical position of D; other cases are possible, but the differences are slight.) A triangle ABU is constructed as in the diagram so that
We are to prove that
and hence that
THE DISCUSSION.
Also
Hence, in ΔACU, ΔADB,
and
so that
Moreover, from the similar triangles,
and
Hence
(ii) The cyclic case; Ptolemy’s theorem.
The final step of the preceding work,
presupposed that U was not on BC, a condition that would certainly hold in general. The case of exception must now receive attention.
THE PROBLEM. Suppose that, in the preceding work, UBC. Then
so that
It is required to prove that
[Note the double arrow ⇔.]
Suppose, first, that equality holds, so that UBC. Then
Hence A, B, C, D are concyclic.
Suppose, next, that A, B, C, D are concyclic. Then
so that BU, BC are the same lines.
Hence UBC, so that the equality holds.
Note. The four points A, B, C, D can be split in two pairs in three ways,
Ptolemy’s theorem asserts that, when the four points are con-cyclic, the sum of products from two of these pairs is equal to the third. The pair which comes “third” is that defined by the diagonals of the cyclic quadrilateral.
[For a more detailed discussion of implications, see E. A. Maxwell, Fallacies in Mathematics, Cambridge University Press (1959) p. 28.]
Problems
1. If D is a point on the arc opposite A of the circumcircle of an equilateral triangle ABC, then AD = BD + CD.
2. AB, PQ are parallel chords of a circle. Prove that
3. Identify the well-known result which is a special case of the theorem of Ptolemy when ABCD is a rectangle.
4. In ΔABC, draw BEAC, CFAB. Prove that BF = BC cos B, CF = BC sin B, and write down similar expressions for CE, BE.
By applying the theorem of Ptolemy ...

Table of contents

  1. Cover
  2. Title Page
  3. Copyright Page
  4. Contents
  5. Preface
  6. Chapter1 · Introduction and Notation
  7. Chapter2 · The Geometry of the Triangle
  8. Chapter3 · Some Circle Theorems
  9. Chapter4 · The Theorems of Ceva and Menelaus
  10. Chapter5 · Harmonic Properties
  11. Chapter6 · Pole and Polar
  12. Chapter7 · Line and Plane
  13. Chapter8 · Some Standard Solid Bodies
  14. Chapter9 · Angles between lines and Planes
  15. Chapter 10 · The Sphere
  16. Chapter 11 · The Nature of Space
  17. Chapter 12 · Transformations
  18. Index

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