Lecture Notes On Mathematical Olympiad Courses: For Junior Section (In 2 Volumes) - Volume 2
eBook - ePub

Lecture Notes On Mathematical Olympiad Courses: For Junior Section (In 2 Volumes) - Volume 2

For Junior SectionVolume 2

  1. 192 pages
  2. English
  3. ePUB (mobile friendly)
  4. Available on iOS & Android
eBook - ePub

Lecture Notes On Mathematical Olympiad Courses: For Junior Section (In 2 Volumes) - Volume 2

For Junior SectionVolume 2

About this book

Olympiad mathematics is not a collection of techniques of solving mathematical problems but a system for advancing mathematical education.

This book is based on the lecture notes of the mathematical Olympiad training courses conducted by the author in Singapore. Its scope and depth not only covers and exceeds the usual syllabus, but introduces a variety concepts and methods in modern mathematics.

In each lecture, the concepts, theories and methods are taken as the core. The examples are served to explain and enrich their intension and to indicate their applications. Besides, appropriate number of test questions is available for reader's practice and testing purpose. Their detailed solutions are also conveniently provided.

The examples are not very complicated so that readers can easily understand. There are many real competition questions included which students can use to verify their abilities. These test questions are from many countries, e.g. China, Russia, USA, Singapore, etc. In particular, the reader can find many questions from China, if he is interested in understanding mathematical Olympiad in China.

This book serves as a useful textbook of mathematical Olympiad courses, or as a reference book for related teachers and researchers.

Contents

  • Volume 2:
    • Congruence of Integers
    • Decimal Representation of Integers
    • Pigeonhole Principle
    • Linear Inequality and System of Linear Inequalities
    • Inequalities with Absolute Values
    • Geometric Inequalities
    • Solutions to Testing Questions
  • and other chapters


Readership: Mathematics students, school teachers, college lecturers, university professors; mathematics enthusiasts.

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Yes, you can access Lecture Notes On Mathematical Olympiad Courses: For Junior Section (In 2 Volumes) - Volume 2 by Jiagu Xu in PDF and/or ePUB format, as well as other popular books in Biological Sciences & Science General. We have over one million books available in our catalogue for you to explore.

Information

Solutions to Testing Questions

Solutions to Testing Questions

Solutions to Testing Questions 16
Testing Questions (16-A)
1.
images
, so the answer is (A).
2.
images
3.
images
images
4.
images
images
5.
images
images
6.
images
from
images
7.
images
images
c < b < a.
8. We have
images
.since
images
9. Let
images
then,
images
10. Since U, V, W > 0, it is sufficient to compare U2, V2, W2. From
images
Therefore U2 > V2 > W2, i.e. W < V < U.
Testing Questions (16-B)
1. Considering negative number cannot be under square root sign, we find |a| = 3, i.e. a = ±3. Further, 3 − a appears in denominator implies a = 3, so a = −3. Thus
images
Thus, the units digit of x is 6 since any positive integer power of 6 always has units digit 6.
2. Let
images
, then the given expression becomes
images
3. More general, we calculate
images
images
Now n = 1998, so
images
.
4. Given
images
, find the value of
images
.
From
images
so that
images
Thus,
images
5. We find [M] first. Let
images
. Then M = A6 and
images
, AB = 2, so
images
Since M = A6, for finding [M], we now consider A6 + B6:
images
which is an integer.
images
yields 0 < B6 < 1, so [M] = A6 + B6 − 1 and
images
Thus,
images
Solutions to Testing Questions 17
Testing Questions (17-A)
1.
images
2.
images
3.
images
4. Let
images
, then a2 + b2 = 16, ab = 1, so
images
5. Let
images
, then a2 + b2 = 8, ab = 3, so
images
6.
images
7. Since
images
, so
images
8. Let
images
, where a, b, c > 0. By taking squares to both sides, then
images
Thus,
images
.
9. Let
images
, then
images
.
It's clear that a ≥ 1. When
images
,< 2, i.e. 1 ≤ a < 5, then
images
. When 5 ≤ a, then
images
Thus,
images
10. It is clear that
images
. On the other hand,
images
Thus, A is the root of the given equation for x.
Testing Questions (17-B)
1. It is clear that ab > 0, i.e. a and b have same signs. Let
images
, then
images
if a = 0 and b < 0; or
images
if b = 0 and a < 0.
A is not defined if a > 0, b > 0 since
images
.
images
Thus,
images
if A is defined.
images
3. Since
images
therefore
images
4. Let
images
, then y ≥ 0 and
images
, so that
images
5.
images
yields
images
, so
...

Table of contents

  1. Cover Page
  2. Title Page
  3. Copyright Page
  4. Preface
  5. Acknowledgments
  6. Abbreviations and Notations
  7. Contents
  8. 16. Quadratic Surd Expressions and Their Operations
  9. 17. Compound Quadratic Surd Form
  10. 18. Congruence of Integers
  11. 19. Decimal Representation of Integers
  12. 20. Perfect Square Numbers
  13. 21. Pigeonhole Principle
  14. 22. [x] and {x}
  15. 23. Diophantine Equations (I)
  16. 24. Roots and Discriminant of Quadratic Equation
  17. 25. Relation between Roots and Coefficients of Quadratic Equations
  18. 26. Diophantine Equations (II)
  19. 27. Linear Inequality and System of Linear Inequalities
  20. 28. Quadratic Inequalities and Fractional Inequalities
  21. 29. Inequalities with Absolute Values
  22. 30. Geometric Inequalities
  23. Solutions to Testing Questions
  24. Index